Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Review: 6

Answer

$17a^3+25a^2$

Work Step by Step

Add $11a^2$ and $14a^2$: $11a^2 + 14a^2=25a^2$ $17a^3+25a^2+a-a$ The a's cancel out, so the final result is $17a^3+25a^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.