Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 1 - Section 1.7 - Exponents and Order of Operations - Exercise Set - Page 74: 80



Work Step by Step

Solve using PEMDAS (The priority list for solving expressions: Parentheses, exponents, [multiplication, division], [addition, subtraction]. For the operations in the brackets, solve from left to right) $\dfrac{3+9^2}{3(10-6)-2^2-1} = \dfrac{3+9^2}{3\cdot 4-2^2-1} = \dfrac{3+81}{3\cdot 4-4-1} = \dfrac{3+81}{12-4-1} = \dfrac{84}{7} = 12$
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