Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 1 - Section 1.7 - Exponents and Order of Operations - Exercise Set: 79

Answer

$3$

Work Step by Step

Solve using PEMDAS (The priority list for solving expressions: Parentheses, exponents, [multiplication, division], [addition, subtraction]. For the operations in the brackets, solve from left to right) $\dfrac{2+4^2}{5(20-16)-3^2-5} = \dfrac{2+4^2}{5\cdot 4-3^2-5} = \dfrac{2+16}{5\cdot 4-9-5} = \dfrac{2+16}{20-9-5} = \dfrac{18}{6} = 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.