# Chapter 1 - Section 1.7 - Exponents and Order of Operations - Exercise Set - Page 73: 65

$4$

#### Work Step by Step

Solve using PEMDAS (The priority list for solving expressions: Parentheses, exponents, [multiplication, division], [addition, subtraction]. For the operations in the brackets, solve from left to right) $\dfrac{7(9-6)+3}{3^2-3} = \dfrac{7\cdot 3+3}{3^2-3} = \dfrac{7\cdot 3 + 3}{9-3} = \dfrac{21+3}{9-3} = \dfrac{24}{6} = 4$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.