#### Answer

$4$

#### Work Step by Step

Solve using PEMDAS (The priority list for solving expressions: Parentheses, exponents, [multiplication, division], [addition, subtraction]. For the operations in the brackets, solve from left to right)
$\dfrac{7(9-6)+3}{3^2-3} = \dfrac{7\cdot 3+3}{3^2-3} = \dfrac{7\cdot 3 + 3}{9-3} = \dfrac{21+3}{9-3} = \dfrac{24}{6} = 4$