#### Answer

$3$

#### Work Step by Step

Solve using PEMDAS (The priority list for solving expressions: Parentheses, exponents, [multiplication, division], [addition, subtraction]. For the operations in the brackets, solve from left to right)
$\dfrac{40+8}{5^2-3^2} = \dfrac{40+8}{25-9} = \dfrac{48}{16} = 3$