Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 9 - Measurement - 9.3 Measuring Weight and Temperature - Exercise Set 9.3 - Page 604: 82

Answer

See below.

Work Step by Step

$C=\frac{5}{9}(F-32)$ hence here $-56.2^\circ F=\frac{5}{9}(-56.2-32)^\circ C=-49^\circ C$ Thus Antarctica is colder, by $-49-(-56.2)=7.2^\circ C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.