Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 9 - Measurement - 9.2 Measuring Area and Volume - Exercise Set 9.2 - Page 593: 5


$\approx 2.15 \text{ in.}^2$

Work Step by Step

Convert by multiplying $\dfrac{1 \text{ in.}^2}{6.5 \text{ cm}^2}$ to obtain: $\require{cancel} =14 \cancel{\text{ cm}^2} \cdot \dfrac{1 \text{ in.}^2}{6.5 \cancel{\text{ cm}^2}} \\=\dfrac{14}{6.5} \text{ in.}^2 \\\approx 2.15 \text{ in.}^2$
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