Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 9 - Measurement - 9.2 Measuring Area and Volume - Exercise Set 9.2: 32

Answer

$16,000~dm^3$

Work Step by Step

We can use the following two conversions. $1 ~kL = 1000~L$ $1~dm^3 = 1~L$ We can convert $16~kL$ to units of $dm^3$. $16~kL = \frac{16~kL}{1}\times \frac{1000~L}{1~kL}\times \frac{1~dm^3}{1~L} = 16,000~dm^3$
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