Answer
\[\left\{ x\le 11 \right\}\].
Work Step by Step
Let us suppose the number is \[x\].
Then, the algebraic form of the inequality is:
\[3\left( 5+x \right)\le 48\]
And now to find out possible values of \[x\] satisfying the inequality the inequality is solved as follows:
\[\begin{align}
& 3\left( 5+x \right)\le 48 \\
& 5+x\le 16 \\
& x\le 11
\end{align}\]
Hence all the real numbers less than or equal to 11 will satisfy the condition.
The set-builder form of the inequality obtained is:
\[\left\{ x|x\le 11 \right\}\]
The set-builder notation for all real numbers that satisfy the given condition is\[\left\{ x\le 11 \right\}\].
