## Thinking Mathematically (6th Edition)

$\left\{ x|x\le 14 \right\}$
Let us suppose the number is$x$. Then, the algebraic form of the inequality is $2\left( 4+x \right)\le 36$ Now, find out possible values of $x$ satisfying the inequality and the inequality is solved as follows: \begin{align} & 2\left( 4+x \right)\le 36 \\ & 4+x\le 18 \\ & x\le 14 \\ \end{align} Hence, all the real numbers less than or equal to 14 will satisfy the condition. The set-builder form of the inequality is obtained as follows: $\left\{ x|x\le 14 \right\}$