Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.3 Applications of Linear Equations - Exercise Set 6.3 - Page 375: 45



Work Step by Step

The provided formula is\[A=\frac{1}{2}bh\] and now solve the formula for \[b\] by multiplying both the sides by \[\frac{2}{h}\] \[\begin{align} & A=\frac{1}{2}bh \\ & \frac{2}{h}\times A=\frac{{}}{{}}\times \frac{1}{{}}b \\ & b=\frac{2A}{h} \end{align}\] The formula \[A=\frac{1}{2}bh\]is for area of a triangle, where \[A=\] area of the triangle, \[b=\] base of the triangle, and\[h=\] height of the triangle. The formula is\[b=\frac{2A}{h}\].
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