## Thinking Mathematically (6th Edition)

The year in which both the countries will have the same population is $2025$ and the population at that time will be $9,900,000$ people.
Consider the equation for the condition at which both the countries will have the same population $10,600,000-28,000x=10,200,000-12,000x$ Here, x is the number of years after the year$2000$ Now, solve the above equation \begin{align} & 10,600,000-28,000x=10,200,000-12,000x \\ & -28,000x+12,000x=10,200,000-10,600,000 \\ & -16,000x=-400,000 \\ & x=25 \end{align} This shows that the year in which the colleges will have the same enrollment is $2000+25=2025$ Now, calculate the population at that time $10,600,000-28,000\left( 25 \right)=9,900,000$ Thus, the year in which both the countries will have the same population is $2025$ and the population at that time will be $9,900,000$ people.