Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.3 Applications of Linear Equations - Exercise Set 6.3 - Page 375: 36

Answer

The year in which both the countries will have the same population is $2025$ and the population at that time will be $9,900,000$ people.

Work Step by Step

Consider the equation for the condition at which both the countries will have the same population $10,600,000-28,000x=10,200,000-12,000x$ Here, x is the number of years after the year$2000$ Now, solve the above equation $\begin{align} & 10,600,000-28,000x=10,200,000-12,000x \\ & -28,000x+12,000x=10,200,000-10,600,000 \\ & -16,000x=-400,000 \\ & x=25 \end{align}$ This shows that the year in which the colleges will have the same enrollment is $2000+25=2025$ Now, calculate the population at that time $10,600,000-28,000\left( 25 \right)=9,900,000$ Thus, the year in which both the countries will have the same population is $2025$ and the population at that time will be $9,900,000$ people.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.