## Thinking Mathematically (6th Edition)

Consider the equation as follows: $\frac{W}{2}-3H=53$ Now, substitute the value of $H$as 12 and find the value of $W$. \begin{align} & \frac{W}{2}-3\left( 12 \right)=53 \\ & \frac{W}{2}=53+36 \\ & W=178\ \text{pounds} \end{align} Here, the value of H is in inches over 5 feet. Now, subtract the above value of the weight with the upper end of the given range. We obtain: $184-178=6\ \text{pounds}$ This shows that the calculated healthy weight is 6 pounds below the upper end of the given range. Hence, the healthy weight of the person with height 6’0” is 178 pounds and the calculated healthy weight is 6 pounds below the upper end of the given range.