Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter Summary, Review, and Test - Review Exercises - Page 336: 104


$3^5 \cdot 3^{-2} = 3^3 = 27$

Work Step by Step

RECALL: For any non-zero real number $a$, $a^m \cdot a^n = a^{m+n}$ Use the rule above to find: $=3^{5+(-2)} \\=3^3 \\=27$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.