Thinking Mathematically (6th Edition)

$\dfrac{7^4}{7^6} = 7^{-2}=\dfrac{1}{49}$
RECALL: For any non-zero real number $a$, $\dfrac{a^m}{a^n} = a^{m-n}$ Use the rule above to find: $\\=7^{4-6} \\=7^{-2}$ RECALL: $a^{-m} = \dfrac{1}{a^m}$ where $a$ is a non-zero real number Use this rule to find: $7^{-2}=\dfrac{1}{7^2} =\dfrac{1}{49}$