Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.4 The Irrational Numbers - Exercise Set 5.4 - Page 296: 63



Work Step by Step

Rationalize the denominator by multiplying $\sqrt{3}$ to both the numerator and denominator: $=\dfrac{15\sqrt{3}}{\sqrt{12}(\sqrt{3})} \\=\dfrac{15\sqrt{3}}{\sqrt{36}} \\=\dfrac{15\sqrt{3}}{6}$ Cancel the common factor, 3, to find: $=\dfrac{5\sqrt{3}}{2}$
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