Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.4 The Irrational Numbers - Exercise Set 5.4 - Page 296: 55



Work Step by Step

Simplify each radical when needed to obtain: $=3\sqrt{25(3)} +2\sqrt{4(3)}-2\sqrt{16(3)} \\=3(5)\sqrt{3} +2(2)\sqrt{3}-2(4)\sqrt{3} \\=15\sqrt{3}+4\sqrt{3}-8\sqrt{3} \\=(15+4-8)\sqrt{3} \\=11\sqrt{3}$
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