Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 4 - Number Representation and Calculation - Chapter Summary, Review, and Test - Review Exercises - Page 245: 34

Answer

\[{{354}_{seven}}\]

Work Step by Step

To multiply two numbers those are not of base 10, follow the below steps, To multiply such numbers, multiply just as it is done in base ten. That is first multiply the right most column numbers and continue same as it is done for base ten but in base seven there are only 0,1,2, 3, 4, 5 and 6, if multiplication exceeds, 6 then change it in base seven. \[\begin{align} {{43}_{seven}} & \\ \times {{6}_{seven}} & \\ \end{align}\] To solve this, follow the steps, \[\begin{align} & {{3}_{seven}}\times {{6}_{seven}}={{18}_{ten}} \\ & {{4}_{seven}}\times {{6}_{seven}}={{24}_{ten}} \\ \end{align}\] And here 18 and 24 are not in base 7, so convert it. \[{{18}_{ten}}=\left( 7\times 2 \right)+\left( 4\times 1 \right)={{24}_{seven}}\] As, 2 is the carry so add 2 in 24, that is \[24+2=26\] \[{{26}_{ten}}=\left( 7\times 3 \right)+\left( 5\times 1 \right)={{35}_{seven}}\] \[\begin{align} & \underline{\begin{align} {{43}_{seven}} & \\ \times {{6}_{seven}} & \\ \end{align}} \\ & \underline{{{354}_{seven}}} \\ \end{align}\] So, here is the solution of the multiplication.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.