Answer
The result of subtraction of indicated base is \[\text{230}{{\text{4}}_{\text{five}}}\].
Work Step by Step
Now, start by subtracting the numbers in right-hand column \[{{1}_{\text{five}}}-{{2}_{\text{five}}}\]. \[{{2}_{\text{five}}}\]is greater than \[{{1}_{\text{five}}}\]so, need borrow from the preceding column.
Now, borrow one group of 5, because in provided question working in base five.
This gives a sum of \[1+5\] or 6 in base ten.
Now, subtract 2 from 6,
\[\begin{align}
& \text{ 1} \\
& \begin{matrix}
\text{ 412}{{\text{1}}_{\text{five}}} \\
-\text{ 131}{{\text{2}}_{\text{five}}} \\
\text{ 4} \\
\end{matrix} \\
\end{align}\]
Now, subtracting the numbers in second right-hand column \[{{1}_{\text{five}}}-{{1}_{\text{five}}}\]
\[\begin{align}
& \text{ 1} \\
& \begin{matrix}
\text{ 412}{{\text{1}}_{\text{five}}} \\
-\text{ 131}{{\text{2}}_{\text{five}}} \\
\text{ 04} \\
\end{matrix} \\
\end{align}\]
Now, perform the subtraction in the third column from the right \[{{1}_{\text{five}}}-{{3}_{\text{five}}}\]. \[{{3}_{\text{five}}}\]is greater than \[{{1}_{\text{five}}}\]so, need borrow from the preceding column.
Now, take borrow one group of 5 because in provided question working in base five.
This gives a sum of \[1+5\] or 6 in base ten.
Now, subtract 3 from 6,
\[\begin{align}
& \text{ 3 1} \\
& \begin{matrix}
\text{ 412}{{\text{1}}_{\text{five}}} \\
-\text{ 131}{{\text{2}}_{\text{five}}} \\
\text{ 304} \\
\end{matrix} \\
\end{align}\]
Now, perform the subtraction in the third column from the right.
\[\begin{align}
& \text{ 3 1} \\
& \begin{matrix}
\text{ 412}{{\text{1}}_{\text{five}}} \\
-\text{ 131}{{\text{2}}_{\text{five}}} \\
\text{ 230}{{\text{4}}_{\text{five}}} \\
\end{matrix} \\
\end{align}\]
Hence, the result of subtraction of indicated base is \[\text{230}{{\text{4}}_{\text{five}}}\].
