## Thinking Mathematically (6th Edition)

Also, take the numbers such that the sum of the numbers is bigger than the base. \begin{align} & \text{ 6 7 } \\ & \text{ 72} \\ & -\text{ 53} \\ & \text{ }\begin{matrix} \text{ 1 4 } \\ \end{matrix} \\ \end{align} The above calculation is done as: For the last column: Since 3 cannot be subtracted from 2, 5 from the adjacent column is carried over to 2, which makes it: ${{7}_{five}}-{{3}_{five}}={{4}_{ten}}=(4\times 1)={{4}_{five}}$ For the first column: ${{6}_{five}}-{{5}_{five}}={{1}_{ten}}=(1\times 1)={{1}_{five}}$