Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 3 - Logic - 3.6 Negations of Conditional Statements and De Morgan's Law - Exercise Set 3.6 - Page 178: 6

Answer

She says yes, and he does not say no.

Work Step by Step

If she says yes, he says no. As we know, the negation of p → q is p ∧ ∼q. p: She says yes. q: He says no. Therefore, the negation of the statement is: She says yes, and he does not say no.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.