Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 3 - Logic - 3.6 Negations of Conditional Statements and De Morgan's Law - Exercise Set 3.6: 6

Answer

She says yes, and he does not say no.

Work Step by Step

If she says yes, he says no. As we know, the negation of p → q is p ∧ ∼q. p: She says yes. q: He says no. Therefore, the negation of the statement is: She says yes, and he does not say no.
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