Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 3 - Logic - 3.6 Negations of Conditional Statements and De Morgan's Law - Exercise Set 3.6 - Page 178: 38

Answer

See below.

Work Step by Step

The negation of $ p\lor q$ is $\sim p\land\sim q$. The negation of $ p\land q$ is $\sim p\lor\sim q$. Thus here the negation is: "$ \sim p \land (\sim q\lor \sim r)$"
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