Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 3 - Logic - 3.2 Compound Statements and Connectives - Exercise Set 3.2 - Page 132: 21

Answer

See below.

Work Step by Step

The statement can be translated to: if $q$ then (always) not $p$, which in logical symbols is: $p \rightarrow q$.
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