Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 3 - Logic - 3.2 Compound Statements and Connectives - Exercise Set 3.2 - Page 132: 15


$\neg q \rightarrow \neg p$

Work Step by Step

The statement is conditional with: antecedent: not a reptile $\neg q$ consequent: not an alligator $\neg p$ Thus, in symbols, we have: $\neg q \rightarrow \neg p$
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