#### Answer

Using Adams's method, the officers are apportioned to the precincts as follows:
Precinct A is apportioned 28 officers.
Precinct B is apportioned 33 officers.
Precinct C is apportioned 53 officers.
Precinct D is apportioned 15 officers.
Precinct E is apportioned 22 officers.
Precinct F is apportioned 29 officers.

#### Work Step by Step

Using the modified divisor of $d = 16$, we can find the modified quota for each precinct.
Precinct A:
$modified~quota = \frac{crimes}{modified~divisor}$
$modified~quota = \frac{446}{16}$
$modified~quota = 27.88$
Precinct B:
$modified~quota = \frac{crimes}{modified~divisor}$
$modified~quota = \frac{526}{16}$
$modified~quota = 32.88$
Precinct C:
$modified~quota = \frac{crimes}{modified~divisor}$
$modified~quota = \frac{835}{16}$
$modified~quota = 52.19$
Precinct D:
$modified~quota = \frac{crimes}{modified~divisor}$
$modified~quota = \frac{227}{16}$
$modified~quota = 14.19$
Precinct E:
$modified~quota = \frac{crimes}{modified~divisor}$
$modified~quota = \frac{338}{16}$
$modified~quota = 21.13$
Precinct F:
$modified~quota = \frac{crimes}{modified~divisor}$
$modified~quota = \frac{456}{16}$
$modified~quota = 28.5$
Using Adams's method, we apportion the officers by rounding the modified quota up to the nearest whole number. The officers are apportioned to the precincts as follows:
Precinct A is apportioned 28 officers.
Precinct B is apportioned 33 officers.
Precinct C is apportioned 53 officers.
Precinct D is apportioned 15 officers.
Precinct E is apportioned 22 officers.
Precinct F is apportioned 29 officers.
Note that the sum of the apportioned officers is 180.