Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.3 Measures of Dispersion - Exercise Set 12.3 - Page 801: 36

Answer

$\approx4.27$

Work Step by Step

The mean of $n$ numbers is the sum of the numbers divided by $n$. Hence the mean: $\frac{13+15+13+18+13+14+23+20+20+24}{10}=17.3$ The standard deviation of $x_1,x_2,...,x_n$ is (where $\overline{x}$ is the mean of the data values): $\sqrt{\frac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+...+(x_n-\overline{x})^2}{n-1}}$. Hence here the the standard deviation is: $\sqrt{\frac{3(13-17.3)^2+(14-17.3)^2+(15-17.3)^2+(18-17.3)^2+2(20-17.3)^2+(23-17.3)^2+(24-17.3)^2}{10-1}}\approx4.27$
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