Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.2 Measures of Central Tendency - Exercise Set 12.2 - Page 792: 55

Answer

See below.

Work Step by Step

The midrange is the sum of the minimum and maximum data value divided by $2$. The mode of $n$ numbers is the number or numbers that appear(s) most frequently. If all items appear the same number of times, then there is no mode. The median of $n$ numbers is the middle number of the numbers when they are in order (and the mean of the middle $2$ numbers if $n$ is even). The mean of $n$ numbers is the sum of the numbers divided by $n$. a) Hence the mean: $\frac{200+97+92+92+64+51+51+50+49+37+34+32+27}{13}\approx67.38$ (thousand) b) Here we have $13$ items, thus the median will be the $7$th item, which according to the table is: $51$ (thousand) c) Hence the modes: $92,51$ (thousand) d) Hence the midrange: $\frac{200+27}{2}=113.5$ (thousand)
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