Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.2 Measures of Central Tendency - Exercise Set 12.2 - Page 792: 50

Answer

See below.

Work Step by Step

The midrange is the sum of the minimum and maximum data value divided by $2$. The mode of $n$ numbers is the number or numbers that appear(s) most frequently. If all items appear the same number of times, then there is no mode. The median of $n$ numbers is the middle number of the numbers when they are in order (and the mean of the middle $2$ numbers if $n$ is even). The mean of $n$ numbers is the sum of the numbers divided by $n$. Here we have $5+3+2+1+1=12$ items, thus the median will be the mean of the $6$th and $7$th item, which according to the graphis: $(20+20)/2=20$. Here the midrange: $\frac{10+50}{2}=30$, the mode: $10$ and the mean: $\frac{5\cdot10+3\cdot20+2\cdot30+1\cdot40+1\cdot50}{12}\approx21.67$.
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