Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - Chapter 11 Test - Page 763: 26

Answer

$\frac{7}{150}$

Work Step by Step

In this case the events are not independent, the first one has probability $\frac{22}{100}$, the second one has probability $\frac{21}{99}$, thus the probability is: $\frac{22}{100}\frac{21}{99}=\frac{7}{150}$
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