Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - Chapter 11 Test - Page 763: 22

Answer

$\frac{3}{5}$

Work Step by Step

We know that $probability=\frac{\text{number of favorable outcomes}}{\text{number of all outcomes}}$ The number of all outcomes is $22+18+10+18+20+12=100$, out of these $10+18+20+12=60$ correspond to the desirable selection. Hence here the probability is $\frac{60}{100}=\frac{3}{5}$
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