Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.8 Expected Value - Exercise Set 11.8 - Page 755: 11

Answer

The second store

Work Step by Step

By definition, the expected value is the sum of each outcome multiplied by its probability. Hence here the expected value for the first store: $\frac{1}{2}\cdot300000+\frac{1}{2}\cdot(-100000)=100000$, the expected value for the second store: $\frac{3}{4}\cdot200000+\frac{1}{4}\cdot(-60000)=135000$. The second store has a higher expected value, thus they should choose that one.
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