Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.6 Events Involving Not and Or; Odds - Exercise Set 11.6 - Page 735: 29

Answer

$\frac{11}{26}$

Work Step by Step

If A and B are not mutually exclusive events, then P(A or B) = P(A)+P(B) - P(A and B) If you are dealt one card from a standard deck, find the probability that you are dealt a heart or a picture card. P(Heart) = $\frac{13}{52}$ P(picture)= $\frac{12}{52}$ P(Heart and picture) = $\frac{3}{52}$ (There are 3 heart picture cards) P(Heart or Picture) = P(Heart) +P(picture) - P(heart and picture) =$\frac{13}{52}$ + $\frac{12}{52}$ - $\frac{3}{52}$ =$\frac{13+12 -3}{52}$ = $\frac{22}{52}$ = $\frac{11}{26}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.