## Thinking Mathematically (6th Edition)

$\displaystyle \frac{12}{67}$
Let events A and B be defined as A = " an Independent is chosen" B = " a Green is chosen" A and B cannot occur simultaneously, so they are mutually exclusive. If $A$ and $B$ are mutually exclusive events, then: $P$ ($A$ or $B$) $=P(A)+P(B)$. P($A$)=$\displaystyle \frac{n(A)}{n(S)}=\frac{8}{30+25+8+4}=\frac{8}{67}$ P($B$)=$\displaystyle \frac{n(B)}{n(S)}=\frac{4}{67}$ $P$ ($A$ or $B$) $=\displaystyle \frac{8+4}{67}=\frac{12}{67}$