#### Answer

$21$

#### Work Step by Step

If we want to choose $k$ elements out of $n$ disregarding the order, not allowing repetition, we can do this in $_{n}C_k=\frac{n!}{k!(n-k)!}$ ways.
Hence here because we have $7$ spots for $2$ people, $_{7}C_2=\frac{7!}{2!(7-2)!}=7\cdot6/2=21$