#### Answer

4495 bowls

#### Work Step by Step

The order of the chosen flavors does not matter.
Combinations, ${}_{n}C_{r}=\displaystyle \frac{n!}{(n-r)!r!}$
${}_{31}C_{3}=\displaystyle \frac{31!}{(31-3)!3!}=\frac{31\times 30\times 29}{1\times 2\times 3}$
$=\displaystyle \frac{31\times 5\times 29}{1\times 1\times 1}= 4495$