Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.2 Permutations - Exercise Set 11.2 - Page 702: 70

Answer

The number of ways to arrange the program at a concert is\[541,900,800\].

Work Step by Step

The first performance is done by jazz group, then the performance can happen in 8, for the second performance there is 8 ways as rock band is performing. For the third performance, there are 7 possibilities for occurring of the jazz as one performance of jazz group is already performed. For a 4thto 7th position, the performance of rock band can be computed in\[_{7}{{C}_{4}}\]ways, for 8th place, there are 6 possibilities as two jazz performance were done before. For the remaining 8 places, the performance can be arranged in\[8!\]. Compute the number of ways to arrange the program at a concert using the equation as shown below: \[\begin{align} & \text{number of ways to arrange the concert}=8\times 8{{\times }_{7}}{{C}_{4}}\times 6\times 8! \\ & =8\times 8\times 7\times \frac{7!}{4!\left( 7-4 \right)!}\times 6\times 8! \\ & =2688\times \frac{7!}{4!3!}\times 40,320 \\ & =3,793,305,600 \end{align}\] Hence, the number of ways to arrange the program at a concert is\[541,900,800\].
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