Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.2 Permutations - Exercise Set 11.2 - Page 702: 68



Work Step by Step

10 aisle seats are taken from 12 aisle seats. Recall: If r items are taken from n items, No. of permutations=$\frac{n!}{(n-r)!}$ Therefore, the number of ways ten people can be seated=$\frac{12!}{(12-10)!}=239,500,800$
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