Answer
The statement is false.
An example of a true statement:
Even though BET and BEE are both three letter words, the number of permutations for each of them differ. BET has 3!=6 permutations. BEE has $\displaystyle \frac{3!}{2!}$=3 permutations.
Work Step by Step
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For the word BET, all three letters are different, so it is true that the number of permutations is $3!=6.$
For the word BEE, there is a group of duplicates (two Es), for which the formula is different,
$\displaystyle \frac{3!}{2!}=\frac{6}{2}=3$
The statement is false.
An example of a true statement:
Even though BET and BEE are three letter words, the number of permutations for each of them differ. BET has 3!=6 permutations. BEE has $\displaystyle \frac{3!}{2!}$=3 permutations.
