#### Answer

False.
$8!=8(7)(6)(5)(4)(3)(2)(1)$

#### Work Step by Step

See: Factorial Notation, page 696.
$n!=n(n-1)(n-2)\cdots(3)(2)(1)$
and
$0!=1$
--------------
The statement is false.
To make it true, change each addition sign to multiplication

Published by
Pearson

ISBN 10:
0321867327

ISBN 13:
978-0-32186-732-2

False.
$8!=8(7)(6)(5)(4)(3)(2)(1)$

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