#### Answer

$\triangle{I} \cong \triangle{II}$ according to the $SSS$ postulate.

#### Work Step by Step

The labels of the figure show that there are two pairs of congruent sides.
The two triangles share a common side, so that will count as another pair of congruent sides.
Thus, the two triangles have three pairs of congruent sides.
Therefore, $\triangle{I} \cong \triangle{II}$ according to the $SSS$ postulate.