Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 6 - Set Theory - Exercise Set 6.4 - Page 381: 5

Answer

See explanation

Work Step by Step

We are asked to prove: \[ \textbf{5. For all } a, b \in B,\quad (a \cdot b) + a = a \] --- ### ✅ Proof: Let \(a, b \in B\). We aim to show: \[ (a \cdot b) + a = a \] --- ### **Step 1**: Use the **Commutative Law** of + \[ (a \cdot b) + a = a + (a \cdot b) \] --- ### **Step 2**: Use the **Absorption Law** From earlier exercises (Exercise 3), we already proved: \[ a + (a \cdot b) = a \] --- ### ✅ Final Answer: \[ \boxed{(a \cdot b) + a = a} \quad \text{(by commutativity and absorption law)} \]
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