Answer
$=\frac{n(n+1)}{2}$
Work Step by Step
$=\frac{(n+1)!}{(n-1)!(n+1-n+1)!}$
$=\frac{(n+1)!}{(n-1)!2!}$
$=\frac{(n-1)!n(n+1)}{(n-1)!2!}$
$=\frac{n(n+1)}{2!}$
$=\frac{n(n+1)}{2}$
Discrete Mathematics with Applications 4th Edition
by Epp, Susanna S.
Published by
Cengage Learning
ISBN 10:
0-49539-132-8
ISBN 13:
978-0-49539-132-6
Chapter 5 - Sequences, Mathematical Induction, and Recursion - Exercise Set 5.1 - Page 244: 76
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