Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 5 - Sequences, Mathematical Induction, and Recursion - Exercise Set 5.1 - Page 244: 68



Work Step by Step

$\frac{((n+1)!)^{2}}{((n)!)^{2}}=\frac{1^{2}\times2^{2}\times...\times(n-1)^{2}\times n^{2}\times(n+1)^{2}}{1^{2}\times2^{2}\times...\times(n-1)^{2}\times n^{2}}$ $=(n+1)^{2}$
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