Answer
True.
Work Step by Step
Since $a|b$, we can write $ka=b$ for some integral k. Then, if we square, $k^2a^2=b^2$. Since $k^2$ is an integer, $a^2|b^2$ because there exists an integer such that the integer times $a^2$ is $b^2$.
Discrete Mathematics with Applications 4th Edition
by Epp, Susanna S.
Published by
Cengage Learning
ISBN 10:
0-49539-132-8
ISBN 13:
978-0-49539-132-6
Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.3 - Page 178: 29
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