Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.1 - Page 162: 48

Answer

$x=2k$ $y=2r$ $k,r \in \mathbb{Z}$ The difference: $|x−y| = 2|k-r|, that is a even number

Work Step by Step

Let $x$ and $y$ be two even integers, they both can be write as: $x = 2k$ $y = 2r$ (with $k$ and $r$ being integers) $k, r \in \mathbb{Z}$ Now we can subtract $x-y$: If $x \geq y$: $\begin{split} x - y & = 2k - 2r \\ & = 2(k - r) \\ \end{split}$ If $x \lt y$ (Similar): $\begin{split} y - x & = 2r - 2k \\ & = 2(r - k) \\ \end{split}$ Since $k-r$ and $r-k$ are integers, then difference between $x$ and $y$ is even, by the definition of even numbers.
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