#### Answer

This is false, as $m^2-1 = (m+1)(m-1)$

#### Work Step by Step

Since $m^2-1 = (m-1)(m+1)$, for any $m \geq 3$, the expression must have at least 2 factors greater than 1, so it cannot be prime. Therefore, the statement is contradicted.

Published by
Cengage Learning

ISBN 10:
0-49539-132-8

ISBN 13:
978-0-49539-132-6

This is false, as $m^2-1 = (m+1)(m-1)$

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