Answer
$29$
Work Step by Step
Step 1:
$(123)_{10}=(64+32+16+8+2+1)_{10}$
$(123)_{10}=((1)2^6+(1)2^5+(1)2^4+(1)2^3+(0)2^2+(1)2^1+(1)2^0)_{10}$
$(123)_{10}=(1111011)_2$
Step 2:
$(94)_{10}=(64+16+8+4+2)_{10}$
$(94)_{10}=((1)2^6+(0)2^5+(1)2^4+(1)2^3+(1)2^2+(1)2^1+(0)2^0)_{10}$
$(94)_{10}=(1011110)_2$
$(1011110)_2 \xrightarrow{flip} (0100001)_2 \xrightarrow{+1} (0100010)_2 = (-94)_{10}$
Step 3:
$(1111011)_2 + (0100010)_2 = (0011101)_2$
Answer:
$(0011101)_2 = (16+8+4+1)_{10} = (29)_{10}$
