#### Answer

$44_{10}$

#### Work Step by Step

$62_{10} = (32 + 16 + 8 + 4 + 2)_{10} = 111110_2 → 00111110$
$−18_{10} = −(16 + 2)_{10}= −10010_2 → 00010010 → 11101101 → 11101110$
Thus the 8-bit representations of 62 and −18 are 00111110 and 11101110 respectively. Adding the 8-bit representations gives
. 0 0 1 1 1 1 1 0
+1 1 1 0 1 1 1 0
$============$
.1 0 0 1 0 1 1 0 0
Truncating the 1 in the 28th position gives 00101100. Since
the leading bit of this number is a 0, the answer is positive.
Converting back to decimal form gives
$00101100 → 101100_2 = (32 + 8 + 4)_{10} = 44_{10}.$
So the answer is 44.