Answer
Hypotenuse $\approx 11.7$ yd.
Work Step by Step
Let $H =$ hypotenuse of the triangle
$a^{2} + b^{2} = c^{2}$
$4^{2} + 11^{2} = H^{2}$
$16 + 121 = H^{2}$
$137 = H^{2}$
$H = \sqrt 137$
$H = 11.704...$
$H \approx 11.7$ yd
Basic College Mathematics (9th Edition)
by Lial, Margaret L.; Salzman, Stanley A.; Hestwood, Diana L.
Published by
Pearson
ISBN 10:
0321825535
ISBN 13:
978-0-32182-553-7
Chapter 8 - Geometry - 8.8 Pythagorean Theorem - 8.8 Exercises - Page 594: 27
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