Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.8 Pythagorean Theorem - 8.8 Exercises - Page 594: 25

Answer

Hypotenuse $\approx 8.5$ in.

Work Step by Step

Let $H = $ the hypotenuse side $a^{2} + b^{2} = c^{2}$ $3^{2} + 8^{2} = H^{2}$ $9 + 64 = H^{2}$ $73 = H^{2}$ $\sqrt 73 = H$ $H = 8.544...$ $H \approx 8.5$ in.
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